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Find the 5th term of the geometric series for which a1 = 1458 and r= 2/3?
Midterms are coming up and I can't figure this out! Can someone please help me!
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- ?Lv 77 years agoFavorite Answer
The nth term of a geometric series is given by ar^n-1
So 1458 * (2/3)^4 = 288
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