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An oil spill of 4399 cubic centimeters is spilled onto a pond and spreads out in a circular shape having a diameter of 536 centimeters. Approximate the thickness of the oil film to four decimal places.
7 Answers
- 7 years agoFavorite Answer
Coma's right.
4399 = pi * r^2 * h
r = 536/2 = 268
4399 = pi * 268^2 * h
h = 4399 / (pi * 268^2)
h = 0.01949550553189038711426040529839
0.0195 cm
- BattleaxeLv 77 years ago
Use the formula for the volume of a cylinder. The height h being the thickness:
V = (pi)(r^2)(h)
r = d/2 = 268cm
call pi 3.1416
4399cm^3 = 3.1416(268^2cm^2)h
4399cm^3 = 225,642cm^2h
h = 4399/225,642 = 0.0195cm or 0.1950mm (take your pick)
thickness of the oil film.
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- az_lenderLv 77 years ago
They want you to assume that pi*R^2*thickness = 4399 cm^3.
It is absurd to suppose that that assumption will be accurate to four decimal places but, oh well, this is in the "math" section, not the "reality" section...
Thickness = (4399 cm^3)/[pi*(268 cm)^2] = 0.0195 cm
...and even the instructions are silly, because if I said "195 microns," they'd still want 4 decimal places, and I'd have to write "194.9551 microns" (insane)...it's not your fault, but I think your teacher is a moron.
- 7 years ago
Okay, first find the circumference of the circle, then you would need to find the height of the cylinder, find the formula for area of a circle, you want the total area to equal 4399, with one dimension of the cylinder, you should be able to plug in numbers into the formula and find it... I could be completely wrong, but I believe this is right, though I have no idea, I am only in 8th grade....
- PolygonLv 77 years ago
Volume of oil on pond = pi*[(536/2)^2]*t
t = thickness of oil
4399 = *pi*[(268)^2]*t
4399 = 225641.75*t
t = 0.0194955 cm
t (rounded) = 0.0195
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- Raj KLv 77 years ago
If thickness is 't' then
4399 =Ï(d/2)²t
ât = 4399/{Ï(268)²}=0.019495 cm=0.1950 mm apprx.