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Calculating resistivity of a gold ring?

How to calculate the resistivity of a ring with:

Diameter: 2cm

Cross section (rectangle): 3,mm by 0.5mm

Voltage: 8.3 mV

Amps: 18

3 Answers

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  • ?
    Lv 7
    7 years ago
    Favorite Answer

    Using the resistance equation .. R = ρL / A .. .. ρ = resistivity

    R = V/i = 8.30^-3V / 18.0A = 4.60^-4 Ω

    Length L = 2πr = 2π x 1.0^-2m = 0.063 m

    Section area A = 0.003m x 0.005m = 1.50^-5 m²

    ρ = RA / L = 4.60^-4 Ω x 1.50^-5 m² / 0.063 m .. .. ►ρ = 1.10^-7 Ωm

  • 7 years ago

    R = resistance , Ω

    ρ = Resistivity, Ωm,

    L = length, m,

    A = area of cross section, m².

    Rectangle length, L = 2(3+0.5) X 10 ‾³m = 7 X 10 ‾³m.

    Area (cr.s.), A = πr² = π(10 ‾⁴)m²

    R = ρ L/A,

    R = V/I = 0.0083/18 = 4.61 X 10 ‾⁴Ω

    = ρ[7 X 10 ‾³/π(10 ‾⁴] = (70/π)ρ Ωm.

    ρ = 4.61 X 10 ‾⁴[π/70] = 20.7 milli Ωm.

  • 7 years ago

    It depends where the voltage is applied:

    between top face and bottom face

    or

    between inside face and outside face

    or

    something else

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