Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
Calculating resistivity of a gold ring?
How to calculate the resistivity of a ring with:
Diameter: 2cm
Cross section (rectangle): 3,mm by 0.5mm
Voltage: 8.3 mV
Amps: 18
3 Answers
- ?Lv 77 years agoFavorite Answer
Using the resistance equation .. R = ρL / A .. .. ρ = resistivity
R = V/i = 8.30^-3V / 18.0A = 4.60^-4 Ω
Length L = 2πr = 2π x 1.0^-2m = 0.063 m
Section area A = 0.003m x 0.005m = 1.50^-5 m²
ρ = RA / L = 4.60^-4 Ω x 1.50^-5 m² / 0.063 m .. .. ►ρ = 1.10^-7 Ωm
- poornakumar bLv 77 years ago
R = resistance , Ω
Ï = Resistivity, Ωm,
L = length, m,
A = area of cross section, m².
Rectangle length, L = 2(3+0.5) X 10 ‾³m = 7 X 10 ‾³m.
Area (cr.s.), A = Ïr² = Ï(10 ‾⁴)m²
R = Ï L/A,
R = V/I = 0.0083/18 = 4.61 X 10 ‾⁴Ω
= Ï[7 X 10 ‾³/Ï(10 ‾⁴] = (70/Ï)Ï Î©m.
Ï = 4.61 X 10 ‾⁴[Ï/70] = 20.7 milli Ωm.
- Steve4PhysicsLv 77 years ago
It depends where the voltage is applied:
between top face and bottom face
or
between inside face and outside face
or
something else