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Proving an indeterminate limit without L'Hopital's rule?
I was helping my girlfriend with her math HW and was surprised when one stumped me. I couldn't figure out how to cancel out terms in the limit to make it calculable without using L'Hopital's rule, which her class hasn't covered.
The limit:
lim(x->π/2) 5(sin(x)-1)/(cos^2(x))
Is there some trig identity that is useful here?
Thanks.
1 Answer
- 7 years agoFavorite Answer
Hint:
try 1 - sin^2x for cos^2x in a factored form, divide out a common factor, then pass to the limit.
