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A ball is thrown vertically downwards from the top of a cliff?
At a time t seconds it is S metres below the top ,where S=5t^2+20t find:
a) how far it has fallen b)its velocity and its acceleration at the end of the first second
1 Answer
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- M3Lv 77 years agoFavorite Answer
a/
s = 5*1² + 20*1 = 25m <------
b/
v = s' = 10t +20 , v(1) = 30 m/s <-----
a = s" = 10 m/s² <-------- constant acceleration
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