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chemistry (acids&bases)?
an acidic solution is prepared by dissolving 0.5 moles of HCl in water,so that the final volume of the solution is 5Liters .determine the PH of the solution
3 Answers
- 7 years agoFavorite Answer
HCl is a strong acid so it will dissociate 100% when dissolved in a solution.
The equation for the pH of a strong acid is (pH = -log[H+])
Since Concentration is measures in moles/Liters, we must set .5moles HCl over 5 Liters. Such as,
(.5m HCl / 5L = .1M HCl)
pH = -Log[.1] = ??
- 7 years ago
okay so you want to find the molarity. molarity is moles/liters so .5 mol/5 liters = 0.1
so then you take -log(H+) since HCl is a strong acid and that should be your pH!
-log(.1) = 1 , so pH of 1 which is a strong aidddddd!
hope that helped!
Source(s): ap chem student, learned about this stuff last week :) - YashLv 57 years ago
The molarity of the resultant solution will be 0.1 M
The formula for pH = -log[h+]
= -log[0.1]
= 1
