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1. Input a number. If it is negative make it positive and display. need pseudo code and flow chart for this .?

3 Answers

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  • justme
    Lv 7
    7 years ago
    Favorite Answer

    if (num < 0){

    num = ~num + 1;

    }

  • 7 years ago

    input number (n)

    if number (n) less than zero

    then let variable (v) = 2 times number (n)

    positive number (p) = n minus v

    display positive number (p)

  • roger
    Lv 7
    7 years ago

    input number

    if <0 multiply by -1

    display

    int num;

    cin >> num;

    cout << ( (nm<0) ?-num:num);

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