Newton"s second law of motion ...........Please help?

A particle of weight 45 N rests on a rough horizontal surface. A cord is attached to the particle and the particle is in limiting equilibrium when the tension in the cord is T newtons. The cord is in the "first quadrant" (just to give you an idea).

(A) Calculate the coefficient of friction and the magnitude of the contact force between the particle and the surface.

Ans: I do not know in which direction the particle is about to move. I cannot calculate the Normal contact force because the angle that the cord makes with the particle (with respect to the horizontal) is not given.

HOW TO Proceed???? ANSWER = 0.72 , 48N

(B) Calculate T and the angle between the cord and the horizontal???????

Ans: 29N , 12 degrees

PLEASE HELP ME OUT.

IF there are some tricks, explain 'em to me..

THANKS.