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What is the pH of a solution formed when 10 mL of an acid with a pH of 3 is diluted to 1 L with pure water?
1 Answer
- 7 years agoFavorite Answer
This problem is just a simple V1M2=V2M2 problem.
First, turn the pH of the acid at 10mL into its molar concentration by using this equation: [H3O+] = 10^-pH. You will get .001 M.
Second convert the 10mL into liters. You will get .010 L
Now, you are ready to use the equation V1M2=V2M2.
(.010L)(.001M)=(1L)(x)
x=1.0^10-5M
You will use this molar concentration to convert it into pH. Use this equation: pH= -log(Molar Concentration)
The answer is pH 5.
Source(s): Pre-Nursing Student
