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? asked in Science & MathematicsChemistry · 7 years ago

BEST ANSWER: Chemistry problem?

NH3 + CO2+ H20 yields NH4HCO3

50.0g of NH3. 80g of CO2 and 2.00 mole of H20 are reacted. What is the maximum number of grams of NH4HCO3 that can be produced?

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  • Roger the Mole
    Lv 7
    7 years ago
    Favorite Answer

    NH3 + CO2 + H2O → NH4HCO3

    (50.0g NH3) / (17.03056 g NH3/mol) = 2.94 mol NH3

    (80g CO2) / (44.00964 g CO2/mol) = 1.82 mol CO2

    2.00 mole of H2O

    All three reactants react in equimolar amounts, and since there is less CO2 than any other reactant, CO2 is the limiting reactant.

    (1.82 mol CO2) x (1 mol NH4HCO3 / 1 mol CO2) x

    (79.05552 g NH4HCO3/mol) = 144 g NH4HCO3

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