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Calculate the molarity of 47.1 g of table sugar (C12H22O11) in 100. mL of solution.?
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- 7 years ago
Molecular weight of table sugar =
C = 12 x 12.01
H = 22 x 1.007
O = 11 x 16.00
Sum them = 342.3 g/mol
47.1 g = (47.1g/342.3g/mol) = 0.138 mol
0.138 mol in 100 mL = 0.138 mol/0.1 L = 1.38M
- servaldadLv 57 years ago
If you don't know the answer, how will you know when you have been given the correct one????????
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