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I have a test tomorrow! please help!?
I need to understand how to do this
how do i find the all the values of alpha from 0 degrees to 360 degrees when the sec3alpha=-square root of 2???
the answers are 45,75,165,195,285,315
1 Answer
- BrainardLv 77 years agoFavorite Answer
sec3alpha=-square root of 2
1/cos(3t) = - sqrt(2)
cos(3t)/1 = 1/-sqrt(2)
= - 1/sqrt(2)
3t = cos^-1(-1/sqrt(2))
= 135, 225, 495, 585,855, 945
t = 135/3, 225/3, 495/3, 585/3 855/3 945/3
= 45, 75, 165, 195 285, 315