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? asked in Science & MathematicsChemistry · 7 years ago

Chemistry question easy 10 points please help :)?

Boiling and freezing point for :

A solution containing 120g of ethylene glycol (C2h6o2) per 400mL of solution

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  • 7 years ago

    Supposing the solvent to be water with density (1.00 g/mL):

    (120 g C2H6O2) / (62.0678 g C2H6O2/mol) / (400 g) x (1000 g) = 4.8334 m

    (0.512 °C/m) x (4.8334 m) = 2.4747 °C change

    100°C + 2.4747 °C = 102.47 °C

    (-1.86 °C/m) x (4.8334 m) = -8.9901°C change

    0°C -8.9901°C = -8.99°C

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