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find x intercepts of (x-4)^2+(y-3)^2=81?

center will be 8, =3 radius = 9

can you tell me if the information is complete?

3 Answers

Relevance
  • 7 years ago

    No, the center is (4, 3). The (x - 4) term tells you the x coordinate of the center is 4.

    The (y - 3) term tells you the y coordinate of the center is 3.

    The x intercepts are where y = 0, so they are the solutions to (x - 4)^2 + 3^2 = 81 or (x -4 )^2 = 81 - 9 = 72.

    Complete to do what?

  • ?
    Lv 5
    7 years ago
  • 7 years ago

    The center is (4, 3) and the radius is 9.

    The x intercepts occur when y = 0

    (x - 4)² + (0 - 3)² = 81

    x² - 8x + 16 + 9 = 81

    x² - 8x - 56 = 0

    x = {8 - √[-8² - 4(1)(56)]}/2 and x = {8 + √[-8² - 4(1)(56)]}/2

    x = 4 - ���72 and x = 4 + √72

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