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Chemistry question, need help!?
Naturally occurring zirconium exists as five stable isotopes: 90Zr with a mass of 89.905 amu (51.45%); 91Zr with a mass of 90.906 amu (11.22%); 92Zr with a mass of 91.905 amu (17.15%); 94Zr with a mass of 93.906 amu (17.38%), and 96Zr with a mass of 95.908 amu (2.80%). Calculate the average mass of zirconium.
2 Answers
- 7 years ago
You have to do what is called a weighted average. Change the percentages to decimals (51.45%-->.5145) and multiply it by the atomic mass of that isotope (89.905 amu).
So this gives .5145 X 89.905 = 46.26 AMU.
Now do the same thing for the other four isotopes and add all of the values.
