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chemistry help?
The specific heat of a human is approximately 3.47 J/g°C.
a) If a 191 lb man eats a candy bar containing 273 Cal, how much will his body temperature increase if all of the calories from the candy bar are converted into heat energy? Remember that a food calorie (Cal) is equal to 1 kcal.
(b) If a 191 lb man eats a roll of candy containing 62.8 Cal, how much will his body temperature increase if all of the calories from the candy are converted into heat energy?
1 Answer
- Roger the MoleLv 77 years ago
a)
273 kcal x (4184 J/kcal) = 1142232 J
191 lb x (453.592 g/lb) = 86636.1 g
(1142232 J) / (3.47 J/g°C) / (86636.1 g) = 3.80 °C
[Of course it doesn't really happen that way. The body regulates its own temperature by, among other things, burning only the amount of carbohydrates necessary to maintain its usual temperature.]
