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Solve the rational inequality. Write the solution set in interval notation. (WILL CHOOSE BEST ANSWER)?
Hello everyone. I'm taking college algebra and on my review for the test I have to take tomorrow morning, I'm having trouble figuring out this question.
Solve the rational inequality. Write the solution set in interval notation.
(4x)/(-5x+18) >/= 10
A) { -infinity, 10/3)
B) (-infinity, 0) U (18/5,infinity)
C) (0,18/5)
D) (10/3, 18/5)
For all the intervals, I've gotten false. Our instructor told us it was D, but I'm afraid I didn't take good notes to memorize how she got that answer. Can anyone here in Yahoo! Answers community help explain it step by step? I will choose the best answers with good explanation. First come first serve.
1 Answer
- TomVLv 77 years agoFavorite Answer
(4x)/(-5x+18) ≥ 10
Since the rational expression is non-negative, the numerator and denominator must have the same sign.
Note -5x+18 ≠ 0 otherwise the expression is undefined.
a) If 4x ≥ 0 then -5x+18 > 0
4x ≥ 0 → x ≥ 0
-5x+18 > 0 → -5x > -18 → x < 18/5
4x ≥ -50x+180
54x ≥ 180
x ≥ 10/3
If 4x ≥ 0 then, 10/3 ≤ x < 18/5
b) If 4x ≤ 0 then -5x+18 < 0
4x ≤ 0 → x ≤ 0,
-5x+18 < 0 → -5x < -18 → x > 18/5
Note that this is an impossible condition because if x ≤ 0, then x cannot be greater than a positive number. Therefore the assumption that 4x ≤ 0 is a false assumption.
We are left with the condition that 4x ≥ 0 which leads to the conclusion that the interval containing x is:
[10/3, 18/5)
which is not shown in the list of choices.
==========================
Note that D is not the correct choice since x can take on the value of 10/3 which is not contained in the interval (10/3, 18/5)
Let x = 10/3, then
4(x)/(-5x+18) ≥ 10
4(10/3)/(-5*10/3 + 18) ≥ 10
(40/3)/(-50/3 + 54/3) ≥ 10
40/(-50+54) ≥ 10
40/4 ≥ 10
10 ≥ 10 : which is a true statement showing that x = 10/3 is a valid solution of the inequality.