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kurtztx
kurtztx asked in Science & MathematicsMathematics · 7 years ago

Hard math question?

Find all possible values of real numbers x and y

x + iy = 3i - ix

I don't get it cause 3i and ix are both imaginary

HELP!?!?

and please show all steps.. thanks

2 Answers

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  • Captain Matticus, LandPiratesInc
    Lv 7
    7 years ago

    x + iy = 3i - ix

    x + iy = i * (3 - x)

    x + iy = 0 + i * (3 - x)

    x = 0

    y = 3 - x = 3 - 0 = 3

    (0 , 3)

  • ?
    Lv 7
    7 years ago

    x and y are reals. That's all they are saying.

    x + iy = 3i - ix

    let's factor out i on the right.

    x + iy = i(3 - x)

    Notice that the right side is an imaginary number rather than a complex number. It has no real part for any value of x besides x=3 when it equals 0. But when x=3 the other side is not zero. This means the only way these two expression can ever be equal is if x = 0. When x = 0

    0 + iy = 3i

    y = 3

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