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kurtztx
kurtztx asked in Science & MathematicsMathematics · 7 years ago

Another hard math question?

I'm sorry I'm soo bad at this

find all possible values for real numbers x and y

|x + iy| = y - ix

so i squared both sides

|x + iy|^2 = (y - ix)^2

(x + iy)(x - iy) = (y - ix)(y - ix)

x^2 + y^2 = y^2 - 2ixy - x^2

2x^2 = -2ixy

x = -iy

is that it?? help...

2 Answers

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  • Eugene
    Lv 7
    7 years ago

    Since |x + iy| is a real number, the equation |x + iy| = y - ix implies x = 0. The equation then reduces to |iy| = y, or |y| = y; this equation is satisfied if and only if y >= 0. So 0 is the only possible for x and the only possible values for y are the nonnegative numbers.

  • Mehedi
    7 years ago

    The third line is wrong...... |x+iy|^2=(x + iy)(x + iy)

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