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Solve: 3x+1 over 6x-2 = 2x+5 over 4x-13?
7 Answers
- 7 years ago
Here is the process:
Cross multiply:
(3x+1)/(6x-2)= (2x+5) (6x-2)
12x^2-39x+4x-13= 12x^2-4x+30x-10
-35x-26x-3=0
Value Of x= -3/61
- Anonymous7 years ago
X=3/77
- Anonymous7 years ago
(3x+1) / (6x-2) = (2x+5) / (4x-13);
(3x+1)*(4x-13) = (2x+5)*(6x-2);
expand both sides:
12(x^2) - 35x -13 = 12(x^2) + 26x -10;
or
61x=-3;
x= -3/61 <---- answer
- PolyhymnioLv 77 years ago
First, cross multiply
(3x + 1)(4x - 13) = (2x + 5)(6x - 2)
12x² - 35x - 13 = 12x² + 26x - 10
61x = -3
x = -3/61
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- BullwinkleLv 77 years ago
(3x + 1) / (6x - 2) = (2x + 5) / (4x - 13)
cross multiply...
(6x - 2)(2x +5) = (3x + 1)(4x - 13)
expand...
12x^2 + 26x - 10 = 12x^2 - 35x - 13
combine like terms and solve...
61x = - 3
x = - 3/61
- ?Lv 77 years ago
(3x+1) / (6x-2) = (2x+5) / (4x-13)
(3x+1)(4x-13) = (2x+5)(6x-2)
12x^2 - 35x - 13 = 12x^2 + 26x - 10
-61x = 3
x = -3/61 << answer
- Anonymous7 years ago
yes
