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Anonymous asked in Science & MathematicsChemistry · 7 years ago

Please Help - Chemistry Question Here - The number of Water Molecules in 333 Grams of AL2(SO4)3 . 19H2O is?

The number of Water Molecules in 333 Grams of AL2(SO4)3 . 19H2O is

A) 18 * 6.022 * 1023

B) 9 * 6.022 * 1023

C) 18

D) 36

1 Answer

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  • 7 years ago
    Favorite Answer

    Are you sure about Al2(SO4)3.19H2O. This forms a number of different hydrates, of which the hexadecahydrate Al2(SO4)3•16H2O and octadecahydrate Al2(SO4)3•18H2O are the most common.

    Looking at the answer choices, I will work with 18H2O

    Molar mass of Al2(SO4)3.18H2O is 666 g/mol

    Mol in 333g = 333/666 = 0.5..mol

    1 mol Al2(SO4)3.18H2O contains 18 mol H2O

    0.500 mol Al2(SO4)3.18H2O contains 18*0.500 = 9.00 mol H2O

    1 mol H2O contains 6.022*10^23 molecules

    9 mol H2O contains 9*6.022*10^23 molecules H2O

    In proper scientific notation this = 5.42*10^24 molecules.

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