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A man of mass 70kg & a child of mass 35kg stand on an ice surface.?
When they push each other by pressing their hands, the man is thrown away on ice @ speed 0.3 ms-1. What will be the distance between the man & the child after 5s ?
2 Answers
- FiremanLv 77 years agoFavorite Answer
By the law of momentum conservation:-
=>Mu = mV
=>70 x 0.3 = 35 x V
=>V = 0.60 m/s
Relative velocity = 0.60 - (-0.30) = 0.90 m/s
Thus distance = Velocity x time = 0.90 x 5 = 4.50 m
- 7 years ago
They shouldn't be messing about on ice. It's dangerous. You should report them. Do you know their names?
