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Need help with calculating work done by friction and work done by weight of a block, as well as max weight for a system to be in equilibrium?
For the first problem, how would the formulas for work done be different from each other for parts a) and b)? And acceleration can be found by Fnet = ma so a = Fnet/m right?
And for the second problem, I'm not exactly sure what I should be doing with that 45 degree angle...
1 Answer
- ?Lv 77 years agoFavorite Answer
1) One might argue that the formula is the same in each case --
work = force * distance.
a) friction Ff = µmgcosΘ, so friction Work = µmgdcosΘ
The distance d = h / sinΘ, so Work = µmgh / tanΘ
Plug in µ, m, g, h and Θ to solve for Work.
b) gravity Work = mgh
Plug in m, g and h to solve for Work.
c) The increase in KE = gravity Work - friction Work. Then solve
KE = ½mv² where v² is the only unknown.
To find the acceleration, use Torricelli's equation:
v² = u² + 2as = 0 + 2as = 2as
where distance s = h / sinΘ. Therefore
a = v²sinΘ / 2h
2. That 45º angle tells you that the vertical and horizontal forces at that point are equal; therefore the maximum weight of A is equal to the maximum friction force under B.
max A = max static friction = µ*Wb = 0.25 * 710N = 180 N
Note: if the angle was 26º, then max A = ½ * 0.25 * Wb
and if the angle was 63º, then max A = 2 * 0.25 * Wb.
(In other words, take the tangent of the angle to find the ratio of A / friction.)