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Math help!?
Im trying so hard to solve this, but i can't figure it out. I have gotten this far on the problem...But I'm not sure what to do now.
((s^-21)(t^9))*((s^24)(t^27))
any tips? Do I FOIL?
Not Solve, but simplify. Sorry
3 Answers
- Rita the dogLv 77 years ago
((s^-21)(t^9))*((s^24)(t^27)) =
s^-21 * s^24 * t^9 * t^27 =
s^(-21+24) * t^(9+27) =
s^3 * t^36
Note: this answer can also be written as s^3 t^36
- Anonymous7 years ago
((s^-21)(t^9))*((s^24)(t^27)) <--- uhh no, not FOIL, but EXPONENT LAWS.
Multiplying this, we should add the exponents of the same bases. (exponent law, (x^m)(x^n) = x^m+n)
((s^-21)(t^9))*((s^24)(t^27))
= (s^-21)(s^24) * (t^9)(t^27)
= (s^-21 + 24) * (t^9 + 27) <--- group the like bases and add the exponents
= (s^3) * (t^36) <--- same as (s^3)(t^36)
The simplified expression is (s^3 t^36)
