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A projectile is fired with an initial speed of 230 m/s and angle of elevation 60°...?
The projectile is fired from a position 120 m above the ground.
I got 2875m for the displacement in the X direction. It's apparently wrong. I calculated the time it takes to fall from the Y distance and then put it in to solve for the X displacement. What is the correct answer?
1 Answer
- 7 years agoFavorite Answer
Your displacement in the X direction is also called the horizontal displacement or the range.
we know :
initial velocity, u = 230 m/s
the angle theta = 60 degrees
g=9.81 m/s^2
range = (u^2 x sin 2 x theta) / g
so you just plug in the values ...
range = ( 230^2 x sin 2 x 60) / 9.81 => ( 52900 x sin120) / 9.81
therefore, range = 46700.0 m
is this answer correct?
