Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and beginning April 20th, 2021 (Eastern Time) the Yahoo Answers website will be in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Trending News
What is the concentration of B at equilibrium when A is heated, and you are given the Kc value?
If a 4.10 M sample of A is heated to 500 K, what is the concentration of B at equilibrium?
A(aq)⇌2B(aq)
Kc=0.00000526
Please explain your process, I would really like to understand this! Thanks in advance!
1 Answer
- FernLv 77 years ago
I worked the problem assuming A and B are gases, since 500K would boil the water.
Initial: 4.10 M
Let x = change in [A]; At equilibrium [A] = 4.10 –x
x moles A x 2 moles B/ 1 mole A = 2x = [B]
K = 5.26 x 10^-6 = (2x)^2 / (4.10 - x)
K = 5.26 x 10^-6 = 4x^2 / (0.410 - x)
Solving the quadratic equation the value of x = 0.00232
