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This math problem is SUPER hard :/ me and my friends can't seem to think of a way to solve it
Help?:
Factory A used 68 more gallons of water than factory B. Factory C used 4 times as much water as Factory A. If the factories used a total of 484 gallons of water, how much water did FACTORY C use?
2 Answers
- 7 years agoFavorite Answer
A = B + 68
therefore
B = A - 68
C = 4A
A + B + C = 484
A + (A - 68) + 4A = 484
6A - 68 = 484
3A - 34 = 242
3A = 276
A = 92
C = 4A
C = 4 * 92
C = 368
- Patrick StarLv 47 years ago
Put the word problems into numbers
Factory A = a
Factory B = b
Factory C = c
a = 68 + b (A used 68 more(+) than B)
c = 4a (C used 4 times (*) more than a)
a + b + c = 484 ( if the factories total(=) to 484)
so
substitute a for what it is equal to
substitute c for what it is equal to, then substitute 4a with what it is equal to
(68 + b) + b + 4(68 + b) = 484
68 + 2b + 272 + 4b
340 + 6b = 484
- 340
6b = 144
----------
6
b = 12
plug in
c = 4a
a = 68 + b
4(68+24)
= 368
Factory C used 368 gallons
