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y = 3 tg (-3x / 2 + pi/2 )?

2 Answers

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  • Favorite Answer

    Olá!

    Quando dois ângulos são complementares, então a tangente de um complemento é igual a cotangente do outro complemento:

    ∗ α + β = π/2 ⇒ β = π/2 - α

    ∗ tg α = cotg β ⇔ tg β = cotg a

    Assim:

    ∗ Y = 3∙tg(-3x/2 + π/2 ) = 3∙tg(π/2 - 3x/2)= 3∙cotg(3x/2)

    Boa sorte!

  • 7 years ago

    Ola aeiou

    y = 3*cotg(3x/2)

    pronto

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