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chemistry help, How many molecules (not moles) of NH3 are produced from 1.54×10^-4g of H2? please explain how to do it?

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  • 7 years ago

    Balanced equation:

    N2 + 3H2 → 2NH3

    3 mol H2 will produce 2 mol NH3

    You have 1.54*10^-4g H2

    Molar mass H2 = 2g/mnol

    mol H2 in ( 1.54*10^-4)g = (1.54*10^-4) / 2 = 7.7*10^-5 mol H2

    This will produce (7.7*10^-5) *2/3 = 5.13*10^-5 mol NH3 produced

    1 mol NH3 contains 6.02*10^23 molecules

    5.13*10^-5 mol NH3 contains ( 5.13*10^-5) *(6.02*10^23) = 3.09*10^19 molecules NH3 produced.

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