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Tiger432
Tiger432 asked in Science & MathematicsChemistry · 7 years ago

Conversion of .95g of liquid water to steam to 100C requires 2.1kJ. What is the molar enthalpy of evaporation of water at 100C?

2 Answers

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  • ?
    Lv 7
    7 years ago
    Favorite Answer

    I'll show the way to do it and you can complete the work.

    (1) write out the process:

    H2O(l, 100 °C)) + heat → H2O(g, 100 °C)

    (2) convert 0.95 g of H2O t omoles H2Ot

    (0.95 g H2O)/(____ g/mol, molar mass of H2O) = ____ moles H2O

    (look up or calculate the molar mass of H2O)

    (3) calculate ∆Hvap on a per mole basis:

    ∆Hvap = (2.1 kJ)/(___ moles H2O) = ____ kJ/mol

  • Roger the Mole
    Lv 7
    7 years ago

    (2.1 kJ) / (0.95 g / (18.01532 g H2O/mol)) = 40 kJ/mol H2O

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