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I know i have to use m=q/c(change in temp.) and change in L=L initial*alpha*change in temp. but how do i find temp?
When 3850 J of heat are added to a 0.13-m-long silver bar, its length increases by 4.03 10-3 m. What is the mass of the bar
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- oubaasLv 76 years agoFavorite Answer
λ ℓ ag = 19*10^-6 °C^-1
4.03*10^-3 = 0.13*λ ℓ ag*ΔT
ΔT = 4.03*10^-3*10^6/(0.13*19) = 1632 °C
Q = m*c ag*ΔT
c ag = 239 J/KG/°C
m = 3850/(1632*239) = 0.010 kg (10 gr)
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