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Spent a lot of time on this... Not working out. Help please?
A 20 kg block slides from rest down a frictionless 18.6 degree ramp.
Find the acceleration of the block.
4 Answers
- Anonymous6 years ago
The component of the force acting parallel to the ramp will be sin(18.6) x 20g =6.379g
g being the constant of acceleration due to gravity (9.81)
as Force = Mass x Acceleration
Acceleration = Force/Mass
Acceleration= 6.379g/20 = 3.13 m/s
- oldprofLv 76 years ago
As there is no friction, a = g sin(theta) = 9.8*sin(radians(18.6)) = 3.13 m/s^2 ANS.
Note the physics; the mass of the block is not germane. Can you see why?
- 6 years ago
Using Newton's 2nd law,
F=ma
m = 20kg
The only force acting the block is gravity that is parallel to the ramp, which is mgsin(angle)
So to find acceleration,
(20kg)(9.81m/s^2)(sin18.6) = (20kg)(a)
a = 3.13 m/s^2
- 6 years ago
mgcos(theta)-mgsin(theta)=ma
g(cos(theta)-sin(phi)=a
9.8m/s^2(cos(18.6)-sin(18.6))=a
a=6.16m/s^2
