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2 C2H2 + 5 O2 → 4 CO2 + 2 H2O. In this reaction the number of grams of oxygen required to react with 0.13 g of acetylene is ________.?

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  • 6 years ago
    Favorite Answer

    Start with the given

    .13gC2H2

    divide by the molar mass to get moles

    .13/26=.005mol C2H2

    multiply by the molar ratio

    .005(5O2/2 C2H2)= .0125

    multiply by the molar mass of O2 (molar mass is 32)

    .0125(32)= .4 grams O2

    Source(s): Honors Chemistry
  • 6 years ago

    .13g C2H2 * (1 mol C2H2)/(26 g) * ( 5 mol O2)/(2 mol C2H2) * (32g)/( mol O2)

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