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A 2.277 g sample of blue copper(II) sulfate pentahydrate, CuSO4•5H2O, is heated carefully to drive off the water....?
The white crystals of CuSO4 that are left behind have a mass of 1.456 g. How many moles of H2O were in the original sample?
Also please explain how. thanks!
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- Roger the MoleLv 76 years ago
All of the mass lost was water, so:
(2.277 g - 1.456 g) / (18.01532 g H2O/mol) = 0.04557 mol H2O
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