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Albert
Albert asked in Science & MathematicsChemistry · 6 years ago

you have 1.23 mol of NaOH in solution and 1.56 mol of Cl2 gas available to react, which is the limiting reactant?

2NaOH(aq) + Cl2(g) → NaCl(aq) + NaClO(aq) + H2O(ℓ)

How many moles of NaClO(aq) could be obtained?

thanks!

1 Answer

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  • Trevor H
    Lv 7
    6 years ago

    Look at your balanced equation:

    2mol NaOH react with 1 mol Cl2 to produce 1 mol NaClO

    You have 1.23 mol NaOH - this will react with 1.23/2 = 0.615 mol Cl2

    You have 1.56 mol Cl2 - which is in excess

    Conclusion: The NaOH is the limiting reactant.

    Again from the equation:

    2 mol NaOH will produce 1 mol NaClO

    You have 1.23 mol NaOH

    This will produce 1.23/2 = 0.615 mol NaClO

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