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How much heat energy, in kilojoules, is required to convert 55.0g of ice at −18.0 ∘C to water at 25.0 ∘C ?
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- Roger the MoleLv 76 years ago
(2.087 J/(g·°C)) x (55.0 g) x (0 − (−18.0)) °C = 2066.13 J to warm the ice to its melting point
(333.6 J/g) x (55.0 g) = 18348 J to melt the ice
(4.184 J/(g·°C) x (55.0 g) x (25.0 − 0) °C = 5753 J to warm the melted ice to 25.0°C
2066.13 J + 18348 J + 5753 J = 26167.13 J = 26.2 kJ total
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