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Determine the empirical formula of the compound??
A compound was analyzed and was found to contain the following percentages of the elements by mass: lithium, 46.46%; oxygen, 53.54%. Determine the empirical formula of the compound.
1 Answer
- 6 years ago
here , we can use the percentage as a mass.
first calculate the mol for every element :
mol = mass/molar mass
mol Li = 46.46/6.94 = 6.69 mol
mol O = 53.54/15.99 = 3.34 mol
second we calculate mol ratio (dividing all mols by the smallest mol value)
Li : 6.69/3.34 = ~ 2 , O : 3.34/3,34 = 1
Li2O1
Empirical formula : Li2O
