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calculate how many grams of the products listed would be produced by complete reaction of 0.450 mol of the first reactant.?
N2H4(l) + O2(g) → N2(g) + 2 H2O(g)
N2 ____ g
H2O ____ g
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- Roger the MoleLv 76 years agoFavorite Answer
(0.450 mol N2H4) x (1 mol N2 / 1 mol N2H4) x (28.01344 g N2/mol) = 12.6 g N2
(0.450 mol N2H4) x (2 mol H2O / 1 mol N2H4) x (18.01532 g H2O/mol) = 16.2 g H2O
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