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Chemistry Homework Help: Stoichiometric Calculations?
How many g of zinc are required to produced 50g of hydrogen when reacting zinc with sulphuric acid?
How many grams of sulphuric acid are required in the previous problem?
I answered:
1. How many g of zinc are required to produced 50g of hydrogen when reacting zinc with sulphuric acid?
Answer-
Zn + H2SO4 = ZnSO4 + H2
Molar mass of Zn – 65.4 g/mol
= 50 g/mol of H * 1 g/mol of H/ 2 moles of H * 65.4 g/mol of Zn/1 mole of Zn
= 50 g/mol of H/2 moles of H * 65.4 g/mol of Zn/1 mole of Zn
= 25 g of H * 65.4 g/mol of Zn/1 mole of Zn
= 1612.5 g/mol of Zn/1 mole of Zn
= 1612.5 grams
= 1612.5 grams of zinc is required to produce 50 g of hydrogen.
2. How many grams of sulphuric acid are required in the previous problem?
Answer-
Molar mass of H2SO4
H- 1 g/mol
My teacher told me the answer is wrong, Any idea where I went wrong?
1 Answer
- Trevor HLv 76 years agoFavorite Answer
The equation tells you that 1 mol Zn will produce 1 mol H2
You want to produce 50g H2
molar mass H2 = 2g/mol
mol H2 in 10g = 50/2 = 25 mol
From the equation you require 25 mol Zn
Molar mass Zn = 65.38g/mol
Mass of 25 mol Zn = 25*65.38 = 1,634.5g Zn required
You had the incorrect molar mass for Zn
1mol H2SO4 will produce 1 mol H2
You require 25 mol H2SO4
Molar mass H2SO4 = 98g/mol
Mass of 25 mol = 25*98 = 2,450g H2SO4 required.
You did not complete the question.
