How many integers below 10^46 have all their digits the same?

Thanks, but I managed to find the answer.

Basically we have a 46 digit limit.

As 10^46 = 1 and 46 zeros, and the number cannot exceed 10^46

So if we consider 111111111 for 46 digits, and for 45, and so on so forth till it's just 1, we have 46 integers which just have 1 as their digits.

So as there are 9 different digits which are integers, 9*46 = 414.

There are infinitely many. -1, -11, -111, ... etc