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How much water must be added to 532 mL of 0.197 M HCl to produce a 0.130 M solution?
How much water must be added to 532 mL of 0.197 M HCl to produce a 0.130 M solution? (Assume that the volumes are additive.)
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- Roger the MoleLv 76 years ago
(532 mL) x (0.197 M) / (0.130 M) = 806 mL total
(806 mL total) - (532 mL HCl) = 274 mL H2O to be added
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