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Is this an identity, i.e. exactly true, or is it only an approximation?

2π =

arctan(35 / 12) + arctan(176 / 57) + arctan(9945 / 3232) + arctan(23808 / 7735) + arctan(1250801244 / 385468067)

Update 2:

@Duke: Thank you. Nice solution. It is indeed a shame that so many distinguished contributors in Y!A Mathematical Forum are no longer with us. The world changes, and not always for the better.

1 Answer

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  • Duke
    Lv 7
    6 years ago
    Favorite Answer

    It is exactly true, follow the link and see my answer to your previous question: the angles here are π/2 - θ₁, π/2 - θ₂, π/2 - θ₃, π/2 - θ₄ and π/2 - θ₅ (notations and corresponding Pythagorean triangles cited in my previous answer), so

    (π/2 - θ₁) + (π/2 - θ₂) + (π/2 - θ₃) + (π/2 - θ₄) + (π/2 - θ₅) =

    = 5π/2 - (θ₁ + θ₂ + θ₃ + θ₄ + θ₅) = 5π/2 - π/2 = 2π as required.

    I notice that from some time both of us keep ourself amused very well - usually you ask interesting questions, I answer them. It is a pity that some distinguished contributors in Y!A Mathematical Forum have abandoned participation.

    P.S. I have had a very interesting time with Y!A these years and intend to stay - answering mathematical questions is enjoyable game for me, this site offers many opportunities. Yet when I have come across to such questions I have usually seen answers from Gianlino, Scythian, late M.Daftary and many others - now I can not compete with them...

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