Probability help? Eight standard dice are tossed. What is the probability that you turn up three 5s?

The probability that an event x with probability p(x) will occur exactly n times in m trials is called the binomial probability:

P=(mCn)*(p(x)^n)*((1-p(x))^(m-n)) where mCn is the binomial coefficient.

We can treat each dice as a trial, so we have 8 trials and we are looking for exactly 3 outcomes in which the number of the dice is 5. So, plugging in n=3, m=8, p(x)=1/6 we get 56*(1/216)*(3125/7776), which is about 0.1042

12%? 4/3? 8%?

I think i did it wrong. i forgot how to do probability

Exactly 3 fives, or at least 5 fives?

p(success) = (number of successful outcomes) / (total number of outcomes)