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Megan Rose
Megan Rose asked in Science & MathematicsChemistry · 6 years ago

knowing that the specific heat capacity of water is 1 cal/g/ degree C calculate the amount of heat needed?

to raise the temp of 500g of water from 20 degrees Celsius to 80 degrees celsuis

3 Answers

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  • Mangal
    Lv 4
    6 years ago

    ∆Q = mc∆T

    = (500 g) (1 cal/g/deg) (60 deg) = 30000 Cal = 30 kCal

    (∆T = 80 deg - 20 deg = 60 deg)

  • Simonizer1218
    Lv 7
    6 years ago

    q = mC∆T = (500 g)(1 cal/g/deg)(60 deg)

    q = 30,000 calories

  • Jan
    Lv 7
    6 years ago

    C = Q /(m*delta T)

    4.18 = Q / (500*60)

    Q = 125.4 kJ

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