PHYSICS LADDER?

Let’s determine the weights of the person and ladder.

For the person, weight = 74 * 9.8 = 725.2 N

For the ladder, weight = 52 * 9.8 = 509.6

This is a torque problem. Since the friction between the wall and the ladder is zero, let the pivot point be at the top of the ladder. The weight of the ladder will produce counter clockwise torque. The friction force will produce clockwise torque. The weight of the ladder is at its center. To determine the torque, we need to determine the horizontal distance from the top of the ladder to its center. Use the following equation.

d = L * cos θ = 6 * cos 60 = 3 meters

Torque = 509.6 * 3 = 1528.8 N *m

Ff = 0.37 * Total weight = 0.37 * (752.2 + 509.6) = 456.876 N

To determine the vertical distance from the top of the ladder to the floor, use the following equation.

d = 3 * sin 60

Torque = 456.876 * 3 * sin 60 = 1,370.628 * sin 60

This is approximately 1187 N * m

To determine the torque that is caused by the person, subtract these two numbers.

Torque = 1528.8 – 1,370.628 * sin 60 = 341.8013329

To determine the horizontal distance from the top of the ladder to the person, divide the torque by the person’s weight.

d = 341.8013329 ÷ 725.2 = 0.470320095 meters

To determine the distance from the top of the ladder to the person, divide by cos 60.

d = 0.470320095 ÷ 0.5 = 0.94264019 meters. To determine the distance from the bottom of the ladder subtract this number from 6 meters.

d = 6 – 0.94264019 = 5.05735981 meters

To determine the vertical distance from the floor to the person, multiply this number by sin 60.

d = 5.05735981 * sin 60 = 4.379802072 meters

This is all the information that can determine for this problem.

An answer requires a question, no? :>)