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An electric charge q1 (-6e) is located at the origin. A second electric charge q2 (+2e) is located a distance "d" from the origin. In terms of "d", what is the distance "x" from q1 where the net electric potential is zero? Assume for this problem that x<d. I imagine you need to use V = kq/r. Please provide an explanation.
1 Answer
- ?Lv 76 years agoFavorite Answer
k(-6e)/x + k(2e)/(d-x) = 0
6e/x = 2e/(d-x)
x/6 = (d-x)/2
x = 3 (d-x)
4x = 3d
x = 3/4 d
