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A particle moves for 8 seconds. It first accelerates from rest and then retards to rest.if retardation is 3 times accln,find time for accln.?
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- ?Lv 76 years agoFavorite Answer
Let the particle accelerate for time = t1 and decelerate for time= t2.
The velocity acquired after t1 seconds is = a t1
a is the acceleration rate.
deceleration rate is 3a. The time to come to rest is
at1 = 3 a t2
t1= 3t2. But t1+ t2=8. This gives t2=2 and t1 =6. It accelerates for 6 seconds and decelerates for 2 seconds.
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