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Value Theorem?
What is the value?
Use the intermediate value theorem to show that the polynomial function has a zero in the given interval.
f(x)=2x^3+2x^2-6x+1;[-4,-2]
find the value of (-4)
2 Answers
- az_lenderLv 76 years ago
f(-4) = -128 + 32 + 24 + 1 = -71.
f(-2) = -16 + 8 + 12 + 1 = +5.
Since the polynomial is a continuous function, it has the value 0 somewhere in the interval.
What do you mean "find the value of (-4)" ?? The value of -4 is -4, duh. Maybe you meant f(-4), which is -71 as shown above.
- Anonymous6 years ago
ƒ(-4) = -71
ƒ(-2) = 5
Since the first bound is negative, and the second bound is positive, and because the polynomial is continuous everywhere within the boundaries, there must be a point between -4 and -2 where ƒ(x) crosses the x-axis.