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pls solve! (10 potins)?
with steps if you may . THANK YOU !
2 Answers
- cidyahLv 76 years agoFavorite Answer
f(x) = e^(-x^2/2)
f'(x) = e^(-x^2/2) (-2x/2)
f'(x) = -x e^(-x^2/2) = 0
x = 0
Consider the intervals (-∞ , 0 ),(0, ∞)
choose one point from each interval and examine the sign of f'(x)
(-∞ , 0) : choose x=-1
f'(-1) = 1/e^(1/2) > 0, so f(x) is increasing on (-∞ , 0 )
(0, ∞): choose x=1
f'(1) = -1/e^(1/2) < 0 ,so f(x) is decreasing on (-∞ , 0 )
lim x-->∞ f(x) = 0
y = 0 is a horizontal asymptote
The maximum occurs at x=0 and the maximum is 1
- Anonymous6 years ago
10 potions huh? ok.....hmm....4 i think