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Physics help, pls solve ! 10 points?
water circulates throughout the house in a hot-water heating system, if the water pumped at a speed of 0.40 m/s through a 4.2 cm diameter pipe in the basement under a pressure of 2.8 atm , what will be the flow speed and pressure in a 2.6 c,m diameter pipe on the second floor 5.0m above ?
with steps , THANK YOU !
1 Answer
- Anonymous6 years agoFavorite Answer
p1 + ρ.V1²/2 + ρ.g.z1 = p2 + ρ.V2²/2 + ρ.g.z2
V1.S1 = Qv = V2.S2
> p2 = p1 + ρ.V1².(1 - (S1/S2)²)/2 - ρ.g.(z2 - z1)
> p2 = 2,8*101325 + 1000*0,4^2*(1 - (4,2/2,6)^4) - 1000*9,81*5
> p2 = 2,34×10^5 Pa = 2,31 atm ◄
> V2 = V1.(d1/d2)² = 0,4*(4,2/2,6)^2 = 1,04 m/s ◄